Find the range of values of X for which the quadratic y=4x^2-10x+12 is increasing?
回答 (1)
2016-11-11 10:18 am
✔ 最佳答案
Vertex has x-coordinate = −b/(2a) = 10/8 = 5/4
Since leading coefficient > 0, then parabola opens up, and is increasing to the right of vertex:
x > 5/4
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161111014805AAQbxLy