2cos(2x) = -1
∴ cos(2x) = -1/2
given cos(θ) = x then θ = 2πn ± cos⁻¹(x), where n∈ℤ [note n∈ℤ means n is a member of the set of integers]
∴ 2x = 2πn ± cos⁻¹(-1/2), where n∈ℤ
∴ 2x = 2πn ± 2π/3, where n∈ℤ
∴ x = πn ± π/3, where n∈ℤ
over the interval of 0 ≤ x < 2π
∴ x = π/3, 2π/3, 4π/3 and 5π/3