請幫忙解１跟４ 感謝～?
回答 (1)
2016-11-10 4:01 am
✔ 最佳答案
1(3^8)^(1/5)*[(9^3)^(1/2)]^(1/3)
=3^(8/5)*[(3^6)^(1/2)]^(1/3)
=3^(8/5)*(3^6)^(1/6)
=3^(13/5)
4
[(27*36)/(2^3*6^3)]^(1/3)
=[(3^3*2^2*3^2)/(2^3*2^3*3^3)]^(1/3)
=[(3^5*2^2)/(2^6*3^3)]^(1/3)
=[3^2*2^(－4)]^(1/3)
=3^(2/3)*2^(－4/3)
收錄日期: 2021-04-30 21:43:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161109194306AAaKzHc