A 466g of water is heated from 8.50 degrees C to 74.60 C. Calculate the amount of heat absorbed (in kilojoules) by the water.?

👨🏻‍🏫 學術台化學

[匿名]

2016-11-09 8:00 am

The specific heat of liquid water is 4.184 J/(g degrees C)

回答 (1)

不用客氣

2016-11-09 8:18 am

Heat absorbed
= m c ΔT
= (466 g) × [4.184 J/g°C] × [(74.60 - 8.50)°C]
= 129000 J
= 129 kJ

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