In order to prepare 50.0 mL pf 0.100 M of NaCl you will add ____ grams of NaCl to ____ mL of water. Help!!?

0.050 L * 0.100 mol/L * 58.44 g NaCl/mol = 0.292 g NaCl made up to 50 mL

As the solution is dilute, the volume of water added is approximately equal to the volume of solution.
Hence, volume of water = 50.0 mL

No. of moles of NaCl = (0.100 mol/L) × (50.0/1000 L) = 0.00500 mol
Molar mass of NaCl = (23.0 + 35.5) g/mol = 58.5 g/mol
Mass of NaCl = (0.00500 mol) × (58.5 g/mol) = 0.293 g (3 sig. fig.)

Answer:
In order to prepare 50.0 mL of 0.100 M of NaCl you will add __0.293__ grams of NaCl to __50.0__ mL of water.