更新1:
Please help, don't know how to do it
2.45 g of an unknown gas at 79 °C and 1.00 atm is stored in a 2.55-L flask. What is the molar mass of the gas?
回答 (1)
2016-11-04 2:14 am
Mass, m = 2.45 g
Absolute temperature, T = (273 + 79) K = 352 K
Pressure, P = 1.00 atm
Volume, V = 2.55 L
Gas constant, R = 0.08206 L atm / (mol K)
Molar mass, M = ? g/mol
PV = nRT and n = (m/M)
Hence, PV = (m/M)RT
and thus M = mRT/(PV)
Molar mass, M = 2.45 × 0.08206 × 352 / (1.00 × 2.55) g/mol = 27.8 g/mol
Absolute temperature, T = (273 + 79) K = 352 K
Pressure, P = 1.00 atm
Volume, V = 2.55 L
Gas constant, R = 0.08206 L atm / (mol K)
Molar mass, M = ? g/mol
PV = nRT and n = (m/M)
Hence, PV = (m/M)RT
and thus M = mRT/(PV)
Molar mass, M = 2.45 × 0.08206 × 352 / (1.00 × 2.55) g/mol = 27.8 g/mol
收錄日期: 2021-05-01 13:05:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161103180804AA3uXfv