Simultaneous equation: 2x+3y=8 7x+2y=12?

Multiply the first given equation by 2 and the second given equation by 3:
4x + 6y = 16
21x + 6y = 36
Subtract the first equation here from the second:
17x = 20
x = 20/17
Substitute this value for x in to 7x+2y=12 (or the first given equation) and solve for y:
7 (20/17) + 2y = 12
140/17 + 2y + 12
140 + 34y + 204
34y = 64
y = 64/34 = 32/17
So the solution is x = 20/17, y = 32/17

2x + 3y = 8
7x + 2y = 12
4x + 6y = 16
21x + 6y = 36
17x = 20
x = 20/17
y = 32/17

2x + 3y = 8, 7x + 2y = 12

7(2x + 3y = 8)

2(7x + 2y = 12)

14x + 21y = 5

14x + 4y = 24

17y = 32

y = 32/17

2x + 3y = 8

2x +3(32/17) = 8

2x = 8 – 3(32/17)

2x = 8(17) – 3(32)/17

x = 8(17) – 3(32)/2(17)

x = 4(17 – 3(4))/17

x = 4(17 - 12)/17

x = 4(5)/17

x = 20/17

2x + 3y = 8 ............(1)

7x + 2y = 12 ............(2)

Multiply (1) by 2 and (2) by 3

4x + 6y = 16 ...........(3)

21x + 6y = 36 .........(4)

Subtract (4) from (3)

- 17x = - 20

x = 20/17

Put in (1)

2(20/17) + 3y = 8

3y = 8 - 40/17

= 96/17

y = 32/17

x = 20\/17 and y = 32\/17

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x= -3y+8/2
x= -2y+12/7