半徑18公分角度40的圓周長,要算湖該怎麼算?
回答 (5)
2016-11-02 2:29 pm
圓周長是直徑X圓周率，再乘360分之40。
是指弧長嗎??
是指弧長嗎??
2016-12-01 11:15 am
18*2*3.14*40/360
=12.56
=12.56
2016-11-06 10:53 am
18*2*3.14/9+18*2
=4*3.14+4*9
=4*12.14
=48.56
=4*3.14+4*9
=4*12.14
=48.56
2016-11-03 11:51 am
圓周長
=2π(18)(40/360)
=4π公分
=2π(18)(40/360)
=4π公分
2016-11-03 6:46 am
面積A = π r² × (40/360)
r=18
面積A = π 18² × (40/360) = 36π
18 × 2 × π/9 + 18 × 2
= 4 × π + 4 × 9
=4 π+36
r=18
面積A = π 18² × (40/360) = 36π
18 × 2 × π/9 + 18 × 2
= 4 × π + 4 × 9
=4 π+36
收錄日期: 2021-04-18 15:43:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161102055638AA9x8GO