Help! Could someone please explain how to solve.?
2016-11-02 4:03 am
Oxalic acid (H2C2O4) has a pKa1= 1.25 and a pKa2= 4.26. At what pH is the HC2O4- concentration equal to the C2O4-2 Concentration?
回答 (1)
2016-11-02 5:04 am
✔ 最佳答案
Consider the second dissociation of oxalic acid :HC₂O₄⁻(aq) + H₂O(l) ⇌ C₂O₄²⁻(aq) + H₃O⁺(aq) …. pKₐ₂ = 4.26
pH = pKₐ₂ - log([HC₂O₄⁻]/[C₂O₄²⁻])
When [HC₂O₄⁻] = [C₂O₄²⁻] :
pH = pKₐ₂ - log(1) = pKₐ₂ = 4.26
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