更新1:
for example.. when 100cm3 of hydrocarbon is passes into a syringe the mass is found to be 0.179g the temperature and pressure are 298k and 100kpa. calculate the relative molecular mass using the ideal gas equation
how do you calculate mass and relative molecular mass using the ideal gas equation?
回答 (1)
2016-10-26 5:13 pm
For the hydrocarbon gas :
Volume, V = 100 cm³ = 0.1 dm³ (or 0.1 L)
Mass, m = 0.179 g
Temperature = 298 K
Pressure, P = 100 kPa
Gas constant, R = 8.314 J / (mol K)
Molar maass, M = ? g/mol
PV = nRT and n = m/M
Then, PV = (m/M)RT
Hecne, M = mRT/(PV)
Molar mass, M = 0.179 × 8.314 × 298 / (100 × 0.1) g/mol = 44.3 g/mol
Relative molecular mass = 44.3
Volume, V = 100 cm³ = 0.1 dm³ (or 0.1 L)
Mass, m = 0.179 g
Temperature = 298 K
Pressure, P = 100 kPa
Gas constant, R = 8.314 J / (mol K)
Molar maass, M = ? g/mol
PV = nRT and n = m/M
Then, PV = (m/M)RT
Hecne, M = mRT/(PV)
Molar mass, M = 0.179 × 8.314 × 298 / (100 × 0.1) g/mol = 44.3 g/mol
Relative molecular mass = 44.3
收錄日期: 2021-05-01 21:14:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161026090137AA1iFGC