高中指數對數數學題求詳解?
回答 (1)
2016-10-25 8:17 am
✔ 最佳答案
SolΣ(k=1 to 9999)_log[(k+1)/k]
=Σ(k=1 to 9999)_[log(k+1)－logk]
=Σ(k=1 to 9999)_log(k+1)－Σ(k=1 to 9999)_logk
=(log2+log3+log4+…+log9999+log10000)－(log1+log2+log3+log9998+log9999)
=log1000－log1
=3－0
=3
收錄日期: 2021-04-30 21:54:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161024233300AASQJ3f