Balancing equation and finding concentration Help. Sapling?

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

Mole ratio H₂SO₄ : KOH = 1 : 2

Initial no. of moles of H₂SO₄ = (0.480 mol) × (0.550 L) = 0.264 mol
Initial no. of moles of KOH = (0.260 mol/L) × (0.500 L) = 0.130 mol

When KOH completely reacts :
No. of moles of H₂SO₄ reacted = (0.130 mol) × 2 = 0.065 mol
No. of moles of H₂SO₄ remains = (0.264 - 0.065) mol = 0.199 mol
Volume of the final solution = (0.550 + 0.500 = 1.050 L
Concentration of H₂SO₄ remains after neutralization = (0.199 mol) / (1.050 L) = 0.190 M

2KOH + H2SO4 --> 2H2O + K2SO4