87.0 mL of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water in mL should you add?

[匿名]

2016-10-24 8:05 am

回答 (1)

胡雪8°

2016-10-24 8:50 am

✔ 最佳答案

C₁V₁ = C₂V₂
(0.400 M) × (87.0 mL) = (0.100 M) × V₂
Final volume, V₂ = 0.400 × 87.0 / 0.100 mL = 348 mL

Volume of water added = (348 - 87) mL = 261 mL

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