How many moles of oxygen are required for the complete combustion of 4.5 moles of butane (C4H10)
I am not sure how to solve this. I have the answer but I want to know how to solve it. Can someone point me in the right direction, I am ripping my hair out
chemistry question about combustion?
2016-10-24 5:41 am
回答 (1)
2016-10-24 5:54 am
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
OR: Mole ratio C₄H₁₀ : O₂ = 2 : 13
No. of moles of C₄H₁₀ = 4.5 mol
No. of moles of O₂ = (4.5 mol) × (13/2) = 29.25 mol
OR: Mole ratio C₄H₁₀ : O₂ = 2 : 13
No. of moles of C₄H₁₀ = 4.5 mol
No. of moles of O₂ = (4.5 mol) × (13/2) = 29.25 mol
收錄日期: 2021-04-18 15:42:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161023214103AADl4Od