Math Help!?

2016-10-24 2:50 am
Find the function f(x) = ax^3 + bx^2 + cx + d for which f(-3) = -108, f(-1)=2, f(1)=8, and f(2) =17

回答 (3)

2016-10-24 2:55 am
Plug in the given numbers to get 4 linear equations
e.g. f(1) = a+b+c+d = 8
2016-10-24 4:35 am
f(x) = ax^3 + bx^2 + cx + d
-a + b - c + d = 2
a + b + c + d = 8
b + d = 5
-27a + 9b - 3c + d = -108
8a + 4b + 2c + d = 17
a = 5 n + 3, b = 6 n - 4, c = -29 n, d = 9 - 6 n, n element Z
f(x) = 8x^3 + 2x^2 - 29x + 3
2016-10-24 3:17 am
Find the function f(x) = ax^3 + bx^2 + cx + d for which,
f(-3) = -108, f(-1)=2, f(1)=8, and f(2) =17.
So,
f(-3) = a(-3)^3 + b(-3)^2 +c(-3) +d = -108,
Or,
-27a +9b -3c +d = -108. .................................................. [1],
Similarly,
f(-1) = -a +b -c +d =


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