2. Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide:
2NaI(aq) + Cl2(g) ----> I2(s) + 2NaCl(aq)
How many grams of sodium iodide, NaI, must be used to produce 46.7 g of iodine, I2?
1. How many moles of NaOH are present in 14.0 mL of 0.210 M NaOH?
2016-10-21 3:12 am
回答 (2)
2016-10-21 4:24 am
✔ 最佳答案
1.No. of moles of NaOH = (0.210 mol/L) × (14.0/1000 mol) = 0.00294 mol
2.
Molar mass of NaI = (23.0 + 126.9) g/mol = 149.9 g/mol
Molar mass of I₂ = 126.9 × 2 g/mol = 253.8 g/mol
2NaI(aq) + Cl₂(g) → I₂(s) + 2NaCl(aq)
OR: Mole ratio NaI : I₂ = 2 : 1
No. of moles of I₂ produced = (46.7 g) / (253.8 g/mol) = 0.184 mol
No. of moles of NaI needed = (0.184 mol) × 2 = 0.368 mol
Mass of NaI needed = (149.9 g/mol) × (0.368 mol) = 55.2 g
2016-10-21 5:29 am
moles = conc x volume
收錄日期: 2021-05-01 13:07:27
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