algebra problem, pls help?
回答 (4)
2016-10-21 12:50 am
What's the question, cretin?
2016-10-21 1:50 am
(x - 2)/√(x² - 4) = (x-2) /sqrt((x-2)(x+2)) = sqrt ((x-2)/(x+2))
2016-10-21 12:45 am
You want to rationalize the denominator? Is that it?
(x - 2)/√(x² - 4)
= (x - 2)√(x² - 4)/(x² - 4)
= (x - 2)√(x² - 4)/[(x - 2)(x + 2)]
= √(x² - 4)/(x + 2), for x ≠ -2, x ≠ 2
Be careful with that exclusion. The given expression is undefined at x = 2, so the simplified expression cannot allow that either. The values between -2 and 2 are not excluded, because no one said the expression had to be real.
(x - 2)/√(x² - 4)
= (x - 2)√(x² - 4)/(x² - 4)
= (x - 2)√(x² - 4)/[(x - 2)(x + 2)]
= √(x² - 4)/(x + 2), for x ≠ -2, x ≠ 2
Be careful with that exclusion. The given expression is undefined at x = 2, so the simplified expression cannot allow that either. The values between -2 and 2 are not excluded, because no one said the expression had to be real.
2016-10-21 12:45 am
Update: Sorry misread question
收錄日期: 2021-04-21 23:48:03
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