How many moles of lead(II) iodide (PbI2) will be produced from 2 mol of potassium iodide (KI)? 2Kl + Pb(NO3)2 ---> PbI2 + 2KNO3?

2016-10-18 4:42 pm

回答 (2)

2016-10-18 4:50 pm

2Kl + Pb(NO₃)₂ → PbI₂ + 2KNO₃
OR: Mole ratio KI : PbI₂ = 2 : 1

No. of moles of KI = 2 mol
No. of moles of PbI₂ = (2 mol) × (1/2) = 1 mol

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2016-10-18 4:43 pm

yeah they can be real pricks

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