Hey guys could you help me answer this question step by step?
Suppose the atmospheric pressure when you performed your experiment was 0.9889 atm at a water temperature of 23.0 degrees Celsius. What is the partial pressure of the oxygen gas (Po2) in the flask? At 23.0 degrees Celsius, the vapour pressure of water is 21.068 torr.
Chemistry: Gas?
2016-10-18 10:06 am
回答 (1)
2016-10-18 10:39 am
Total pressure = (Partial pressure of air) + (Vapor pressure of water)
(0.9889 atm) × (760 torr) = (Partial pressure of air) + (21.068)
Partial pressure of air = 730.5 torr
The air contains about 20% of oxygen.
Partial pressure of O₂ = (730.5 torr) × 20% = 146.1 torr
(0.9889 atm) × (760 torr) = (Partial pressure of air) + (21.068)
Partial pressure of air = 730.5 torr
The air contains about 20% of oxygen.
Partial pressure of O₂ = (730.5 torr) × 20% = 146.1 torr
收錄日期: 2021-04-18 15:44:35
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