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A 250 mL standard solution of HCl needs to be prepared for a titration. Calculate the required volume of 11 M HCl required to make the standard solution so that 10 mL aliquots from the standard solution contain 0.0056 moles of HCl.
Answer : 13mL
Chemistry?
2016-10-18 8:49 am
回答 (2)
2016-10-18 9:57 am
✔ 最佳答案
No. of moles of HCl in 10 mL aliquot = 0.0056 molNo. of moles of HCl in 250 mL solution = (0.0056 mol) × (250/10) = 0.14 mol
No. of moles of HCl in the 11 M HCl = 0.14 mol/L
Volume of 11 M HCl needed = (0.14 mol/L) / (11 mol/L) = 0.013 L = 13 mL
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