A 0.389g sample of KHP will be titrated with NaOH solution with an assumed concentration of 0.100 M.?
回答 (2)
2016-10-18 2:23 am
The formula of KHP is HC₈H₄O₄K.
Molar mass of KHP = (12.0×8 + 1.0×5 + 16.0×4 + 39.0) g/mol = 204.0 g/mol
KHP + NaOH → KNaP + H₂O
OR: Mole ratio KHP : NaOH = 1 : 1
No. of moles of KHP reacted = (0.389 g) / (204.0 g/mol) = 0.00191 mol
No. of moles of NaOH needed = 0.00191 mol
Volume of NaOH needed = (0.00191 mol) / (0.100 mol/L) = 0.0191 L = 19.1 L
Molar mass of KHP = (12.0×8 + 1.0×5 + 16.0×4 + 39.0) g/mol = 204.0 g/mol
KHP + NaOH → KNaP + H₂O
OR: Mole ratio KHP : NaOH = 1 : 1
No. of moles of KHP reacted = (0.389 g) / (204.0 g/mol) = 0.00191 mol
No. of moles of NaOH needed = 0.00191 mol
Volume of NaOH needed = (0.00191 mol) / (0.100 mol/L) = 0.0191 L = 19.1 L
2016-10-18 2:21 am
(0.389 g KHP) / (204.22 g KHP/mol) x (1 mol NaOH / 1 mol KHP) / (0.100 mol/L NaOH) = 0.0190 L =
19.0 mL NaOH
19.0 mL NaOH
收錄日期: 2021-04-18 15:44:52
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