Calculate the number of grams of oxygen required to convert 18.0 g of glucose to CO2 and H2O? Also compute the # of grams of CO2 produced?

Molar mass of C₆H₁₂O₆ = (12.0×6 + 1.0×12 + 16.0×6) g/mol = 180 g/mol
Molar mass of O₂ = 16.0 × 2 g/mol = 32.0 g/mol
Molar mass of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol

The molecular formula of glucose is C₆H₁₂O₆.

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

According to the equation, mole ratio C₆H₁₂O₆ : O₂ = 1 : 6
No. of moles of C₆H₁₂O₆ = (18.0 g) / (180 g/mol) = 0.1 mol
No. of moles of O₂ required = (0.1 mol) × 6 = 0.6 mol
Mass of O₂ required = (32.0 g/mol) × (0.6 mol) = 19.2 g

According to the equation, mole ratio C₆H₁₂O₆ : CO₂ = 1 : 6
No. of moles of C₆H₁₂O₆ = 0.1 mol
No. of moles of CO₂ produced = (0.1 mol) × 6 = 0.6 mol
Mass of CO₂ produced = (44.0 g/mol) × (0.6 mol) = 26.4 g

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