√(x-2) - √2 的微分怎麼算?

Sol
y=√(x－2)－√2
y’=dy/dx
=d[√(x－2)－√2]/dx
=d[(x－2)^(1/2)－√2]/dx
=d(x－2)^(1/2)/dx
=[d(x－2)^(1/2)/d(x－2)]*[d(x－2)/dx]
=(1/2)*(x－2)^(1/2－1)
=1/[2(x－2)^(1/2)]
=1/[2√(x－2)]
or
y=√(x－2)－√2
y+√2=√(x－2)
y^2+2y√2+2=x－2
2yy’+2y’√2=1
y’(2y+2√2)=1
y’[2√(x－2)－2√2+2√2]=1
y’[2√(x－2)]=1
y’=1/[2√(x－2)]

y=√(x－2)－√2
dy/dx=0.5(x-2)^-0.5