What is the gas density of N2 at 300K?
I know PV=nRT so would the formula change to d=PM/RT ?
so d= (1atm) (28g N2) / (.08206) (300K)
d= 1.14
Is this method/answer correct?
How to find gas density given temperature?
2016-10-17 5:11 pm
回答 (1)
2016-10-17 5:38 pm
You method and numerical answer are correct, but units (g/L) are missed in the answer.
My presentation is shown as follows :
Pressure, P = 1 atm
Molar mass, M = 14.0 × 2 g/mol = 28.0 g/mol
Absolute temperature, T = 300 K
Gas constant, R = 0.08206 L atm / (mol K)
Density, d = ? g/L
PV = nRT and n = (m/M)
Then, PV = (m/M)RT
PM = (m/V)RT
PM = dRT
Then, d = PM/(RT)
Density, d = 1 × 28.0 / (0.08206 × 300) g/L = 1.14 g/L
My presentation is shown as follows :
Pressure, P = 1 atm
Molar mass, M = 14.0 × 2 g/mol = 28.0 g/mol
Absolute temperature, T = 300 K
Gas constant, R = 0.08206 L atm / (mol K)
Density, d = ? g/L
PV = nRT and n = (m/M)
Then, PV = (m/M)RT
PM = (m/V)RT
PM = dRT
Then, d = PM/(RT)
Density, d = 1 × 28.0 / (0.08206 × 300) g/L = 1.14 g/L
收錄日期: 2021-05-01 13:42:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161017091106AA83L8U