What mass of baking soda would completely react with 3.8 g of acetic acid?

The formulae of acetic acid and baking soda are CH₃COOH and NaHCO₃ respectively.
Molar mass of CH₃COOH = (12.0×2 + 1.0×4 + 16.0×2) g/mol = 60.0 g/mol
Molar mass of NaHCO₃ = (23.0 + 1.0 + 12.0 + 16.0×3) g/mol = 84.0 g/mol

CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂
OR: Mole ratio CH₃COOH : NaHCO₃ = 1 : 1

No. of moles of CH₃COOH = (3.8 g) / (60 g/mol) = 0.063 mol
No. of moles of NaHCO₃ = 0.063 mol
Mass of NaHCO₃ = (84.0 g/mol) × (0.063 mol) = 5.3 g (to 2 sig. fig.)

(The answer is to 2 sig. fig. because the mass of acetic acid (3.8 g) is to 2 sig. fig.)