因式分解 要步驟謝謝 下面的^2等於二次方 p^2-(p+q)^2?
回答 (2)
2016-10-17 10:14 am
p^2-(p+q)^2
=p^2-(p^2+2pq+q^2)
= - (2pq+q^2)
= - q(2p+q)
=p^2-(p^2+2pq+q^2)
= - (2pq+q^2)
= - q(2p+q)
2016-10-17 4:05 am
p^2-(p+q)^2
=[p-(p+q)][p+(p+q)]
=-q(2p+q)
=[p-(p+q)][p+(p+q)]
=-q(2p+q)
收錄日期: 2021-04-18 15:41:41
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