20cm3 sample of butyne is burnt in 150cm3 of oxygen. 2C4H6+11O2---8CO2+6H2O. What volume of O2 reacts and what volume of CO2 produced?
回答 (1)
2016-10-16 11:19 am
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
OR: Volume ratio C₄H₆ : O₂ : CO₂ = 2 : 11 : 8
Initial volume of C₄H₆ = 20 cm³
Initial volume of O₂ = 150 cm³
If C₄H₆ completely burns, volume of O₂ needed = (20 cm³) × (11/2) = 110 cm³ < 150³
Hence, O₂ is in excess, and C₄H₆ completely burns.
Volume of C₄H₆ burns = 20 cm³
Volume of O₂ reacts = (20 cm³) × (11/2) = 110 cm³
Volume of CO₂ produced = (20 cm³) × (8/2) = 80 cm³
OR: Volume ratio C₄H₆ : O₂ : CO₂ = 2 : 11 : 8
Initial volume of C₄H₆ = 20 cm³
Initial volume of O₂ = 150 cm³
If C₄H₆ completely burns, volume of O₂ needed = (20 cm³) × (11/2) = 110 cm³ < 150³
Hence, O₂ is in excess, and C₄H₆ completely burns.
Volume of C₄H₆ burns = 20 cm³
Volume of O₂ reacts = (20 cm³) × (11/2) = 110 cm³
Volume of CO₂ produced = (20 cm³) × (8/2) = 80 cm³
收錄日期: 2021-04-20 16:33:14
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