0.950 mol of Na2S in 1.75L in solution
31.9 mol of MgS in 847 mL of a solution
can you show steps too? i honestly am kinda clueless with this stuff. i would really appreciate someone explaining this to me
Calculate molarity of the following solution?
2016-10-14 5:39 pm
回答 (2)
2016-10-14 6:02 pm
Molarity = (No. of moles of solute) / (Volume of solution in L)
For 0.950 mol of Na₂S in 1.75L of solution :
Molarity = (0.950 mol) / (1.75 L) = 0.543 M
For 31.9 mol of MgS in 847 mL of solution :
Molarity = (31.9 mol) / (847/1000 L) = 37.7 M
For 0.950 mol of Na₂S in 1.75L of solution :
Molarity = (0.950 mol) / (1.75 L) = 0.543 M
For 31.9 mol of MgS in 847 mL of solution :
Molarity = (31.9 mol) / (847/1000 L) = 37.7 M
2016-10-14 5:42 pm
molarity = moles / liters
0.950 mol / 1.75L <<< use a calculator
31.9 mol of MgS in 847 mL of a solution
31.9 mol / 0.847 L <<< use a calculator
0.950 mol / 1.75L <<< use a calculator
31.9 mol of MgS in 847 mL of a solution
31.9 mol / 0.847 L <<< use a calculator
收錄日期: 2021-05-01 13:06:09
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