✔ 最佳答案
Vo = 23.2 m/s at Θ = 34.6°
Voy = Vo(sin Θ) = 13.174 m/s
Vox = Vo(cos Θ) = 19.097 m/s
time to reach max height = t = Voy/g = 13.174/9.81 = 1.3429 s
max height = H = 1/2gt² = 8.8458 m
Range = Vox • 2t = 51.2907 m
Horizontal distance from nozzle location to max height location = Range/2 ≈ 25.6 m ANS*
Assumption would be valid for water stream to behave as a projectile (actually a continuous stream of projectiles) but if such assumption is to be mentioned, the MAIN assumption applying to ALL projectile motion might also be mentioned => that this answer assumes there is "no air friction".