How do I find the 15th term in the expansion?
回答 (1)
2016-10-12 5:09 am
The binomial coefficient C(20,15) = C(20,5) = 20*19*18*17*16 /(5*4*3*2*1) = 15504
The 15th term of (a+b)^20 is C(20,15) a^6 b^14.
Binomial theorem. In your case a=(4/3)x^2 and b=-3/(2x).
The 15th term of (a+b)^20 is C(20,15) a^6 b^14.
Binomial theorem. In your case a=(4/3)x^2 and b=-3/(2x).
收錄日期: 2021-04-20 16:41:16
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