How would I graph this function? y=x^2+4x+9 I really need help! Thank you!?
回答 (1)
2016-10-12 12:25 am
Put the equation is vertex form.
y = x^2 + 4x + 9
y = x^2 + 4x + 4 + 5
y = (x + 2)^2 + 5
Draw a point at the vertex is (-2, 5).
Pick an x-coordinate < -2 and one > -2. For example,
let x = -4.
y = (-4 + 2)^2 + 5 = 9
Draw a point at (-4, 9).
Let x = 0.
y = (0 + 2)^2 + 5 = 9
Draw a point at (0, 9).
Draw a parabola through the three points.
y = x^2 + 4x + 9
y = x^2 + 4x + 4 + 5
y = (x + 2)^2 + 5
Draw a point at the vertex is (-2, 5).
Pick an x-coordinate < -2 and one > -2. For example,
let x = -4.
y = (-4 + 2)^2 + 5 = 9
Draw a point at (-4, 9).
Let x = 0.
y = (0 + 2)^2 + 5 = 9
Draw a point at (0, 9).
Draw a parabola through the three points.
收錄日期: 2021-04-21 23:37:32
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