Please help 16g of methane reacts with 64g of oxygen to give 36g of water. Calculate the mass of carbon dioxide produced.?

By the law of conservation of mass :
Total mass of reactants = Total mass of products
Mass of methane + Mass of oxygen = Mass of carbon dioxide + Mass of water
(16g) + (64 g) = Mass of carbon dioxide + (36 g)
Hence, Mass of carbon dioxide produced = 44 g

...
let's check the mole ratios

. . 16 g . . . . . . 64 g . . . . . . . . . . . . . . . . .36 g
. . CH4 . . + . . 2O2 . . → . . CO2 . . + . . 2 H2O
(16g/mol) . . . . (32g/mol) . . . . . . . . . . . . . . (18g/mol)
. 1 mol . . . . .. 2 mol . . . . . .. . . . . . . . . . .2 mol
they all aer right in line withe the coefficients in the balanced equation
so
1 mol of CO2 will result
1 mol * 44 g/mol = 44 g of CO2

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