有三條直線2x-y+4=0,x+y-4=0,x-5y+2=0此三條直線所圍成的之三角形的三個頂點座標為?

2016-10-10 2:48 pm

回答 (2)

2016-10-16 1:52 am
2x-y+4=0
x+y-4=0
x=0,y=4

x+y-4=0
x-5y+2=0
x=3,y=1

2x-y+4=0
x-5y+2=0
x=-2,y=0
三個頂點座標為(0,4),(3,1),(-2,0)
2016-10-10 2:57 pm
有三條直線2x-y+4=0,x+y-4=0,x-5y+2=0此三條直線所圍成的之三角形的三個頂點座標為?
Sol
(1) 2x-y+4=0,x+y-4=0
(2x-y+4)+(x+y-4)=0
3x=0
x=0
y=4
頂點1=(0,4)
(2) 2x-y+4=0,x-5y+2=0
5(2x-y+4)-(x-5y+2)=0
9x+18=0
x=-2
y=0
頂點2=(-2,0)

(2) x+y-4=0,x-5y+2=0
(x+y-4)-(x-5y+2)=0
6y-6=0
y=1
x=3
頂點3=(3,1)


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