計算933平方-2*934平方+935平方 求解!!!?
回答 (2)
2016-10-09 2:28 am
933^2-2(934^2)+935^2
=(934-1)^2-2(934^2)+(934+1)^2
=934^2-2(934)+1-2(934)+934^2+2(934)+1
=2(924)^2-2(934)-2(934)+2(934)+2
=2
=(934-1)^2-2(934^2)+(934+1)^2
=934^2-2(934)+1-2(934)+934^2+2(934)+1
=2(924)^2-2(934)-2(934)+2(934)+2
=2
2016-10-08 11:19 am
Sol
933^2－2*934^2+935^2
=(933^2－934^2)+(935^2－934^2)
=(933－934)*(933+934)+(935－934)*(935+934)
=－(933+934)+(935+934)
=2
933^2－2*934^2+935^2
=(933^2－934^2)+(935^2－934^2)
=(933－934)*(933+934)+(935－934)*(935+934)
=－(933+934)+(935+934)
=2
收錄日期: 2021-04-18 15:39:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161008030318AA9gvaA