1.設f(x)=1250x^6-2790x^5-3125x^4+707x^3+100x^2+45x-62，則f(x)除以x-3的餘式為何?

f(x)=1250x^6-2790x^5-3125x^4+707x^3+100x^2+45x-62
當x-3=0
x=3
f(3)=1250(3)^6-2790(3)^5-3125(3)^4+707(3)^3+100(3)^2+45(3)-62
餘式=f(3)=217

Sol
1250＋2790－3125＋707＋100＋45－ 62｜3
…..…3750＋2880－735－__84＋48＋279｜
────────────────────────────
1250＋_960－_245－_28＋_16＋93｜217
餘式=217

8+9