✔ 最佳答案
(25.8 g NaCl) / (58.4430 g NaCl/mol) / (0.100 kg) = 4.4146 mol/kg = 4.4146 m NaCl
Supposing complete ionization:
NaCl → Na{+} + Cl{-} [two ions total] [i = 2]
(4.4146 m NaCl) x (2 mol ions / 1 mol NaCl) = 8.8292 m ions
(1.86 °C/m) x (8.8292 m) = 16.4°C change
0.0°C - 16.4°C = - 16.4°C