國一數學的數學問題?
回答 (3)
2016-10-06 3:19 pm
(2^1000)-(2^999)
=(2^999)(2-1)
=2^999
=(2^999)(2-1)
=2^999
2016-10-06 1:23 pm
Sol
2^1000－2^999
=2*2^999－2^999
=(2－1)*2^999
=2^999
2^1000－2^999
=2*2^999－2^999
=(2－1)*2^999
=2^999
2016-10-07 1:51 pm
2^1000－2^999
=2*2^999－2^999
=(2－1)*2^999
=2^999
=2*2^999－2^999
=(2－1)*2^999
=2^999
收錄日期: 2021-04-18 15:39:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161006052008AAjQBPP