Factorization?
回答 (4)
2016-10-06 10:59 am
✔ 最佳答案
96= ( -12)x( -8)so x^2+ax+96=(x-8)(x-12)=x^2-20x+96
s= -20, b= -8
2016-10-13 12:49 am
L.H.S.=x^2+ax+96
R.H.S.=(x+b)(x-12)
=x^2+bx-12x-12b
By comparing like terms,we have
-12b=96
b=-8
a=-8-12
a=-20
R.H.S.=(x+b)(x-12)
=x^2+bx-12x-12b
By comparing like terms,we have
-12b=96
b=-8
a=-8-12
a=-20
2016-10-09 2:48 am
x^2+ax+96≡ (x+b)(x-12)
When x=12
144+12a+96=0
a=-20
x^2-20x+96≡ (x+b)(x-12)
(x-12)(x-8)=(x+b)(x-12)
b=-8
When x=12
144+12a+96=0
a=-20
x^2-20x+96≡ (x+b)(x-12)
(x-12)(x-8)=(x+b)(x-12)
b=-8
2016-10-06 10:48 am
if x^2+ax+96≡ (x+b)(x-12) ,find the values of a and b
Sol
x^2+ax+96≡ (x+b)(x－12)
Set x=12
144+12a+96=0
12+a+8=0
a=－20
x^2－20x+96=(x+b)(x－12)
b=－8
Sol
x^2+ax+96≡ (x+b)(x－12)
Set x=12
144+12a+96=0
12+a+8=0
a=－20
x^2－20x+96=(x+b)(x－12)
b=－8
收錄日期: 2021-04-18 15:41:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161006023056AAj33dm