Factorization?

2016-10-06 10:30 am

if x^2+ax+96≡ (x+b)(x-12) ,find the values of a and b.

回答 (4)

2016-10-06 10:59 am

✔ 最佳答案

96= ( -12)x( -8)
so x^2+ax+96=(x-8)(x-12)=x^2-20x+96
s= -20, b= -8

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2016-10-13 12:49 am

L.H.S.=x^2+ax+96
R.H.S.=(x+b)(x-12)
=x^2+bx-12x-12b
By comparing like terms,we have
-12b=96
b=-8
a=-8-12
a=-20

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2016-10-09 2:48 am

x^2+ax+96≡ (x+b)(x-12)
When x=12
144+12a+96=0
a=-20
x^2-20x+96≡ (x+b)(x-12)
(x-12)(x-8)=(x+b)(x-12)
b=-8

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2016-10-06 10:48 am

if x^2+ax+96≡ (x+b)(x-12) ,find the values of a and b
Sol
x^2+ax+96≡ (x+b)(x－12)
Set x=12
144+12a+96=0
12+a+8=0
a=－20
x^2－20x+96=(x+b)(x－12)
b=－8

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