Before the first endpoint only K3PO4 is reacting. PO4^3– (aq) + H3O+ (aq) ---> HPO4^2– (aq) + H2O (l)?
2016-10-05 6:11 pm
If at the first equivalence point 14.92 ml of 0.1094 M HCl is consumed, how many mmol of K3PO4 were present in the sample?
回答 (2)
2016-10-05 6:21 pm
✔ 最佳答案
K₃PO₄(aq) + HCl(aq) → K₂HPO₄(aq) + H₂O(l)No. of milli-moles of HCl reacted = (0.1094 mmol/mL) × (14.92 mL) = 1.632 mmol
According to the above equation, mole ratio K₃PO₄ : HCl = 1 : 1
No. of milli-moles of K₃PO₄ present in the sample = 1.632 mmol
2016-10-05 6:20 pm
0.01492 L X 0.1094 mol/L = 1.632X10^-3 mol X (1000 mmol/1 mol) = 1.632 millimoles K3PO4
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