Please explain why x^2 • -x^-2 = -1?

since x^-2 = 1/x^2

so x^2 • -x^-2 = x^2 • -1/x^2 = -1

By indice law : a⁻ⁿ = 1/aⁿ
Hence, x⁻² = 1/x²

L.H.S.
= x² • -x⁻²
= x² • (-1) • x⁻²
= (-1) • x² • x⁻²
= (-1) • x² • (1/x²)
= (-1) • (x²/x²)
= (-1) • 1
= -1
= R.H.S.

Hence, x² • -x⁻² = -1

x^2 * -x^-2 can also be written as x^2/-x^2 which is equal to -1

　
x² • −x⁻²
= x² • −1/x²
= (x²/x²) • −1
= 1 • −1
= −1

Well,

this is not correct

x^2 * x^-2 = x^(2 - 2) = x^0 = 1

hope it' ll help !!

Note that this is only true if x is not zero