✔ 最佳答案
Mass of water, m = 421 g
Specific heat capacity, c = 4.18 J /g °C
Initial temperature, Ti = 19.0°C
Heat absorbed by water, E = 80.6 kJ = 80600 J
Let T°C be the final temperature.
E = m c ΔT
80600 = 421 × 4.18 × (T - 19.0)
T = 19.0 + [80600 / (421 × 4.18)]
Final temperature, T = 64.8°C