因式分解(有式) *=次方
拜託快一點 (4a-5b)*2-7c(5b-4a)
3a-bx+3b-ax
4ax-3by+6sy-2bx
3p+2q*2-q-6pq
-m*2-3mr-3pr-mp
x*4+cx*3-2x*3-2cs*2?
回答 (3)
✔ 最佳答案
因式分解
(1) (4a-5b)^2-7c(5b-4a)
=(4a-5b)^2+7c(4a-5b)
=(4a-5b+7c)(4a-5b)
(2) 3a-bx+3b-ax
=(3a+3b)-(ax+bx)
=3(a+b)-x(a+b)
=(3-x)(a+b)
(3) 4ax-3by+6ay-2bx
=(4ax+6ay)-(3by+2bx)
=2a(2x+3y)-b(3y+2x)
=(2a-b)(2x+3y)
(4) 3p+2q^2-q-6pq
=(3p-q)+(2q^2-6pq)
=(3p-q)+2q(q-3p)
=(1-2q)(3p-q)
(5) -m^2-3mr-3pr-mp
=-(m^2+3mr)-(3pr+mp)
=-m(m+3r)-p(m+3r)
=-(m+p)(m+3r)
(6) x^4+cx^3-2x^3-2cx^2
=(x^4+cx^3)-(2x^3+2cx^2)
=x^3(x+2c)-2x^2(x+2c)
=(x^3-2x^2)(x+2c)
(4a-5b)^2-7c(5b-4a)
=(4a-5c)(4a-5b+7c)
3a-bx+3b-ax
=3(a+b)-(a+b)x
=(a+b)(3-x)
4ax-3by+6ay-2bx
=2x(2a-b)+3y(2a-b)
=(2a-b)(2x+3y)
3p+2q^2-q-6pq
=q(2q-1)+3p(1-2q)
=(2q-1)(q-3p)
-m^2-3mr-3pr-mp
=-m(m+3r)-p(3r+m)
=-(m+3r)(m+p)
x*4+cx*3-2x*3-2cx*2
=x^3(x-2)+cx^2(x-2)
=x^2(x+c)(x-2)
收錄日期: 2021-04-18 15:35:00
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