國中數學因式分解(5)?

2016-09-25 1:15 pm

回答 (1)

2016-09-26 12:19 am
1
x^2-x-2=(x-2)(x+1)
設 x^3-2x^2+ax+b=p(x)(x^2-x-2)
f(2)=8-8+2a+b=0
2a+b=0
f(-1)=-1-2-a+b=0
a-b=-3
3a=-3
a=-1
b=2

(1)
x(p-q)-(x^2-pq)
=xp-qx-x^2+pq
=(xp+pq)-(x^2+qx)
=p(x+q)-x(x+q)
=(p-x)(x+q)

(2)
3ax-2bx+cx+3ay-2by+cy
=x(3a-2b+c)+y(3a-2b+c)
=(x+y)(3a-2b+c)

(3)
(x+1)^2(y-2)+(2-y)^2(x+1)
=(x+1)^2(y-2)+(y-2)^2(x+1)
=(x+1)(y-2)*[(x+1)+(y-2)]
=(x+1)(y-2)(x+y-1)


收錄日期: 2021-04-30 21:53:28
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