國中數學因式分解（4）?
回答 (2)
2016-10-22 11:58 am
1)
4a^2b^2-8a^2b+12ab^2
=4ab(ab-2a+3b)
2)
(x+2)^2+3(x+2)
=(x+2)[(x+2)+1]
=(x+2)(x+3)
3)
(x-3)(x-2)-(x-4)(2-x)
=(x-2)(2x+1)
4)
4x^2+x-4x-1
=x(4x+1)-(4x+1)
=(4x+1)(x-1)
4a^2b^2-8a^2b+12ab^2
=4ab(ab-2a+3b)
2)
(x+2)^2+3(x+2)
=(x+2)[(x+2)+1]
=(x+2)(x+3)
3)
(x-3)(x-2)-(x-4)(2-x)
=(x-2)(2x+1)
4)
4x^2+x-4x-1
=x(4x+1)-(4x+1)
=(4x+1)(x-1)
2016-09-25 2:15 pm
1)4a^2b^2-8a^2b+12ab^2
=4ab(ab-2a+3b)
2)(x+2)^2+3(x+2)
=(x+2)[(x+2)+1]
3)(x-3)(x-2)-(x-4)(2-x)
=x(x-3)-2(x-3)-x(2-x)+4(2-x)
=2x^2-9x+2
4)4x^2+x-4x-1
=x(4x+1)-1(4x+1)
=(4x+1)(x-1)
=4ab(ab-2a+3b)
2)(x+2)^2+3(x+2)
=(x+2)[(x+2)+1]
3)(x-3)(x-2)-(x-4)(2-x)
=x(x-3)-2(x-3)-x(2-x)+4(2-x)
=2x^2-9x+2
4)4x^2+x-4x-1
=x(4x+1)-1(4x+1)
=(4x+1)(x-1)
收錄日期: 2021-04-18 15:35:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160925051045AArfCn6