國中數學因式分解（2）?
回答 (2)
2016-09-25 8:39 am
✔ 最佳答案
4)1-y+ay-a(y^2)=(1-y)+ay(1-y)
=(1-y)(1+ay)
5)x^3+x^2+x+1
=(x^2)(x+1)+(x+1)
=(x+1)(x^2+1)
6)(2x^3-5)-(2x-5)x
=(2x^3-5)-2x^2+5x
=(2x^3-2x^2)+(5x-5)
=2x^2(x-1)+5(x-1)
=(x-1)(2x^2+5)
2016-09-25 10:14 am
4)
1-y+ay-ay^2
=(1-y)+ay(1-y)
=(1-y)(1+ay)
5)
x^3+x^2+x+1
=x^2(x+1)+(x+1)
=(x+1)(x^2+1)
6)
(2x^3-5)-(2x-5)x
=2x^3-2x^2+5x-5
=2x^2(x-1)+5(x-1)
=(x-1)(2x^2+5)
1-y+ay-ay^2
=(1-y)+ay(1-y)
=(1-y)(1+ay)
5)
x^3+x^2+x+1
=x^2(x+1)+(x+1)
=(x+1)(x^2+1)
6)
(2x^3-5)-(2x-5)x
=2x^3-2x^2+5x-5
=2x^2(x-1)+5(x-1)
=(x-1)(2x^2+5)
收錄日期: 2021-04-18 15:37:50
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