X的4次方加上4如何因式分解？？ 請詳述解法 謝謝?
回答 (2)
2016-09-28 9:17 am
x^4+4
= x^4+4x^2+4-4x^2
= (x^2+2)^2-(2x)^2
= (x^2-2x+2)(x^2+2x+2)
= x^4+4x^2+4-4x^2
= (x^2+2)^2-(2x)^2
= (x^2-2x+2)(x^2+2x+2)
2016-10-13 3:37 am
x^4+4
=-(-x^4-4)
=-(-x^2^2-2^2)
=-(-x^2-2)(-x^2+2)
=-(-x^4-4)
=-(-x^2^2-2^2)
=-(-x^2-2)(-x^2+2)
收錄日期: 2021-04-18 15:33:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160921053326AA9uq1T