Given that a^2+b^2=10 and (a+b)^2=4, find the value of (a-b)^2. Please give steps. Thank you.?
回答 (1)
2016-09-16 11:32 am
Sol
10－4=(a+b)^2－(a^2+b^2)=2ab
ab=3
(a－b)^2
=a^2－2ab+b^2
=(a^2+b^2)－2ab
=10－6
=4
10－4=(a+b)^2－(a^2+b^2)=2ab
ab=3
(a－b)^2
=a^2－2ab+b^2
=(a^2+b^2)－2ab
=10－6
=4
收錄日期: 2021-04-30 21:57:41
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