Can a right triangle have sides measuring 6, 8, and 2?

Let h be the hypotenuse -- the biggest side
Right triangle property
h^2 = a^2 + b^2

8^2 = 64

6^2 + 2^2 = 40 ---> not equal 64 ---> so not a right angled triangle

No. (And if you construct this it is going to be a straight line)

To check apply Pythagoras's theorem: sq rt of 36 + 4 does not equal 8

No. Because 2^2 + 6^2 = 40 which is not equal to 8^2 = 64

no ,2+6 =8 (third side) cant be
the sum of two sides greater than the third side(rule

This cannot even be a triangle. It's a line, not a "right triangle".
>
> John (gnujohn)

No

since sum of squares of each side making right angle on a triangle has be equal to square of the opposite side of the right angle that is 2 ^2 + 6 ^2 has to be equal to 8^2 , but we do not find so , rather sum of square of each side is 40 and which is not equal to 64 , therefore it is not a right angle triangle.

No.