15x-2x(10-7x) =? (麻煩列式)?
回答 (6)
2016-10-01 7:53 am
hbhzvbznzbbzhbzhbvvsv
2016-10-13 12:58 am
15x-2x(10-7x)
=15x-20x-14x^2
=-5x-14x^2
=15x-20x-14x^2
=-5x-14x^2
2016-09-18 11:27 pm
15x-2x(10-7x)
=15x-20x+14x ∧2
=(14x∧2)-5x
=x(14x-5)
=15x-20x+14x ∧2
=(14x∧2)-5x
=x(14x-5)
2016-09-14 3:51 pm
15x-2x(10-7x)
=15x-20x+14x ∧2
=(14x∧2)-5x
=x(14x-5)
=15x-20x+14x ∧2
=(14x∧2)-5x
=x(14x-5)
2016-09-11 11:31 am
15x-20x+14x(x)
=14x^2-5x
=14x^2-5x
2016-09-11 2:33 am
15x-2x(10-7x)
=15x-(2x)(10)-2x(-7x)
=15x-2(10)x-(-1)(2)(7)(x)(x)
=15x-20x+14x^2
=14x^2 +(15x-20x)
=14x^2 +(15-20)x
=14x^2 +(-5)x
=14x^2 -5x
=15x-(2x)(10)-2x(-7x)
=15x-2(10)x-(-1)(2)(7)(x)(x)
=15x-20x+14x^2
=14x^2 +(15x-20x)
=14x^2 +(15-20)x
=14x^2 +(-5)x
=14x^2 -5x
收錄日期: 2021-04-18 15:31:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160909025614AAHKzmh