Write the expression as the algebraic sum of power functions?
回答 (5)
2016-09-07 4:10 pm
y = (x-x⁻¹)²
= (x - 1/x)²
= x² - 2 + 1/x²
= (x - 1/x)²
= x² - 2 + 1/x²
2016-09-07 4:05 pm
y=(x-1/x)^2
=>
y=x^2-2x(1/x)+(1/x)^2
=>
y=x^2-2+1/x^2
=>
y=x^2-2x(1/x)+(1/x)^2
=>
y=x^2-2+1/x^2
2016-09-07 3:17 pm
(x-1/x)^2
x^2 - 2(x)(1/x) + 1/x^2
x^2 -2 + 1/x^2
x^2 - 2(x)(1/x) + 1/x^2
x^2 -2 + 1/x^2
2016-09-07 3:13 pm
Drop the course.
2016-09-07 3:13 pm
x^2 - 2 + 1/(x^2)
note that 2 is 2x^0
note that 2 is 2x^0
收錄日期: 2021-04-21 21:40:52
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